Drinking and Driving Among High School Students The percentage of high school students who drink and drive stood at 17.5% at the beginning of 2001 and declined linearly to 10.3% at the beginning of 2011.

a. Find a linear function f(t) giving the percentage of high school students who drink and drive in year t, where t=0 corresponds to the beginning of 2001.
b. At what rate was the percentage of students who drink and drive dropping between 2001 and 2011?
c. If the trend continues, what will the percentage of high school students who drink and drive be at the beginning of 2014?

Step-by-step explanation:

The percentage of high school students who drink and drive at the beginning of 2001   =   17.5%

The percentage of high school students who drink and drive at the beginning of 20011   =   10.3%

Rate of decrease = 17.5 - 10.3 / 10

= .72

The required linear function

f(t) =  - 0.72 x t + 17.5

b ) Rate of decrease in percentage = (17.5 - 10.3) / 10

= .72 %

c )  Percentage of high school students who drink and drive  at the beginning of 2014

t = 2014 - 2011 = 13

f(t) =  - 0.72 x t + 17.5

= - .72 x 13 + 17.5

= 8.14 %

damm bro the struggle

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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