You flip 3 coins. Is the probability of obtaining 2 heads and 1 tail in any order the same as the probability of obtaining a head, than a head then a tale?

the probability of obtaining 2 heads and 1 tail in any order is higher than the probability of obtaining a head, than a head then a tail

Step-by-step explanation:

since the probability (p) of obtaining 2 head and 1 tail in any order is

P1 = p of obtaining ( H , H ,T) + p of obtaining ( H , T ,H ) + p of obtaining ( T , H ,H ) = 3*p of obtaining ( H , T ,H)

assuming a fair coin then p heads = p tails = 0.5

thus since each flip is independent from the others

p( H , H ,T)=p( H , T ,H )= p( T , H ,H )= P=0.5*0.5*0.5= 1/8

thus P1 =3*1/8=3/8

while the probability of obtaining a head, than a head then a tail is

P2= p of obtaining ( H , T ,H)= 1/8

then P1=3/8 >P2=1(8

therefore the probability of obtaining 2 heads and 1 tail in any order is higher than the probability of obtaining a head, than a head then a tail

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