For a certain animal, suppose that the number of babies born is independent for each pregnancy. this animal has a 70% chance of having one baby and a 30% chance of having 2 babies at each pregnancy. let X be a random variable that represents the total number of babies if the animal gets pregnant twice. construct a table showing the probability distribution of X.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b