Let f ( x ) = x 2 + 6 x + 6 f ( x ) = x 2 + 6 x + 6 , and g ( x ) = 1 g ( x ) = 1 . Find all values for the variable x x , for which f ( x ) = g ( x ) f ( x ) = g ( x ) .

Therefore the value of x are = -1 and -5 for which f(x)=g(x).

Step-by-step explanation:

Given,

f(x)=x²+6x+6    and    g(x)=1

f(x)=g(x)

⇒x²+6x+6=1

⇒x²+6x+6-1=0

⇒x²+6x+5=0

⇒x²+5x+x+5=0

⇒x(x+5)+1(x+5)=0

⇒(x+5)(x+1)=0

⇒x+5=0     or       x+1=0

⇒x=-5                     x=-1

Therefore the value of x are = -1 and -5.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

i'm sure goog can you get that answer