Determine the dimensions of the constants A and B from the following derivative where y has the dimension of length and t has the dimension of time. (Use the following as necessary: L and T, where L is the unit of length and T is the unit of time.) dy/dt

1. A=L/T^3

2. B=L/T

Step-by-step explanation:

Assume the equation y = At^3 +Bt describes the motion of a particular object,

with y having the dimension of length and t having the dimension of time. Determine the dimensions of the constants A and B. (Use the following as necessary:

L and T, where L is the unit of length and T is the unit of time.)

could be the possible concluding part of this question

let us give equate  the right hand side with dimension L

y=At^3 +Bt

y=(At^3)

y=has the dimension of length and t has the dimension of time, recall

L=AT^3

A=L/T^3

for B

L=BT

B=L/T

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer: 40392

step-by-step explanation:

10098 x 4 = 40392