Use Stokes' Theorem to evaluate ∫CF⋅dr∫CF⋅dr. In each case CC is oriented counterclockwise as viewed from above.

F(x, y,z)=3i+2(x+yz)j+4(xy−z√)kF(x, y,z)=3i+2(x+yz)j+4(xy−z)k

Where CC is the boundary of the part of the plane 2x+4y+z=42x+4y+z=4 in the first octant.