Two guy wires from the top of a 200-foot radio antenna are anchored to the ground by two large concrete posts. The antenna is perpendicular to the ground and between the two posts. If the angles of depression from the top of the antenna to each of the posts is 46o and 48o respectively, then the distance between the two posts is:

373.22 feet

Step-by-step explanation:

The attached photo contains the diagram illustrating the scenario. 2 right angle triangles ACD and BCD are formed.

The distance between the two posts is AD + BD

To determine AD, we would apply the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Tan 46 = 200/AD

AD = 200/Tan 46 = 200/1.0355

AD = 193.14

To determine BD, we would also apply the tangent trigonometric ratio. Therefore

Tan 48 = 200/BD

BD = 200/Tan 48 = 200/1.1106

BD = 180.08

Therefore, the distance between the two posts is

193.14 + 180.08 = 373.22 feet

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

srry ask agian

step-by-step explanation: