I need help with this question

first option

Step-by-step explanation:

let the point of intersection of the two sticks be 'O'

then, get back to the question,

isha wants KM=KN 1

and LM=LN 2

for eqn.1,

in  ΔKON and ΔKOM

if, ∠KON=∠KOM 3

   and MO = NO, 4

since KO is common

therefore ΔKON ≅ ΔKOM

but eqn.3 and eqn.4 are only possible

if KN is perpendicular to MN and it bisects MN

similarly, for eqn.2

in ΔLOM and ΔLON

they would be congruent only

if KN is perpendicular to MN and it bisects MN

hence, first option

(pls ask for doubts if any

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.