Find the equation of the line with slope m = 3/2 that contains the points (2,1).

y=3/2x-2

Step-by-step explanation:

m=3/2 A(2,1)=A(x1, y1) ... x1=2,y1 =1

y-y1=m(x-x1)

y-1=3/2(x-2)

y-1=3/2x-3/2*2

y-1=3/2x-3

y=3/2x-3+1

y=3/2x-2

hiking down a winding trail.

step-by-step explanation:

it would open into a square depending on the type of envelope i’m not sure about the second part