Chloe wants to wrap a present in a box for sarah. The top and bottom of the box is 8in by 3in, the sides are both 3in by 2in and the front and back are 8in by 2in. How much wrapping paper wii Chloe need to wrap the present?

92 sq. inches

Step-by-step explanation:

Total paper required = total surface area

Surface area of a cuboid = 2[(l×b) + (l×h) + (b×h)],

Where 'l' is the length, 'b' is the breadth and 'h' is the height

For the box, total surface area = 2[(8×3) + (3×2) + (8×2)]

=2[24 + 6 + 16]

=2[46]

= 92 sq. inches

Step-by-step explanation:

The box is in the shape of a cuboid.

The top and bottom of the box is 8in by 3in. The area of the top and the bottom of the box would be

2 × 8 × 3 = 48 square inches.

The sides are both 3in by 2in. The area of the two opposite sides of the box would be

2 × 3 × 2 = 12 square inches.

The front and back are 8in by 2in. The area of the front and back would be

2 × 8 × 2 = 32 square inches.

The amount of wrapping paper that Chloe needs to wrap the present would be

48 + 12 + 32 = 92 square inches

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5