How to make subject b in a= b-2/b-5

b =

Step-by-step explanation:

Given

a = ← multiply both sides by (b - 5)

a(b - 5) = b - 2 ← distribute left side

ab - 5a = b - 2 ← subtract b from both sides

ab - b - 5a = - 2 ← add 5a to both sides

ab - b = 5a - 2 ← factor out b from each term on the left side

b(a - 1) = 5a - 2 ← divide both sides by (a - 1)

b =

b = ab -5a + 2

Step-by-step explanation:

Given a = b-2/b-5

Cross multiply

a(b-5) = b-2

Using the distributive property we have

axb -ax5 = b-2

ab -5a = b -2

Add 2 to both sides

ab - 5a +2 = b -2+2

ab - 5a + 2 = b

Therefore b = ab -5a + 2

where is the image?

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse