Find an equation of the line. Write the equation using function notation through left parenthesis 4 comma negative 4 right parenthesis; perpendicular to 7y=x-14

The question is:

Find an equation of the line. Write the equation using function notation through (4, -4); perpendicular to 7y = x - 14

The equation of the line is f(x) = -7x + 24

Step-by-step explanation:

We are given a line:  7y = x - 14.    

We need to find the slope, and that means we need to rewite the slope in the form y = mx + c. Where m is the slope of the line.

7y = x - 14

Divide both sides by 7

y = (1/7)x - 2

Comparing this with y = mx + c, we can see that the slope, m = 1/7

We want to write an equation that is perpendicular to the equation 7y = x - 14.

The slope of a line perpendicular to a slope m is -1/m.  

We have a slope 1/7, a line perpendicular to it has slope -7/1.

Now, we use the point-slope form to find our equation:    

.

The points given is  . Substitute the values into the point-slope form equation.

y - (-4) = -7/1 (x - 4)

y + 4 = -7x + 28

The solution has to be in terms of y, so that we can write it using function notation.

Doing that,

y = -7x + 28 - 4

y = -7x + 24

To write it in function notation, simply put y = f(x)

so  f(x) = -7x + 24.

l.ln.lln.k.nkl

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0