A water tank is formed with the combination of
cylinder and hemisphere. The total height of the
tank is 20 m and base area is 616 m². If the tank is
filled with water at the rate of 45 paisa per liter,
what is the total cost to fill the water? Find it.

421160 Rupees

Step-by-step explanation:

Base area of cylinder = π × r^2

=> 616 = 22/7 × r^2

r^2 = (616 × 7) ÷ 22

= 4312 ÷ 22

= 196

Therefore r = √196

= 14 m

Total height of the tank = 20 m

Therefore height of cylinder

= 20 - 14

= 6 m

Volume of water tank

= Volume of cylinder + Volume of hemisphere

= π × r^2 × h + 2/3 × π × r^3

= 22/7 × 14 × 14 × 6 + 2/3 × 22/7 × 14

× 14 × 14

= 22/7 × 14 × 14 ( 6 + 2/3 × 14 )

= 616 ( 15.3 )

= 9424.8 m^3

= 9424800 l

( to convert m^3 to litre, multiply volume value by 1000 )

Total cost to fill water

= 9424800 × 45

= 424116000 paise

= 4241160 Rupees

bottom left

step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

hope this !

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!