A science experiment requires a 10% hydrogen peroxide solution. How much hydrogen peroxide must be added to 16 ounces of water to yield a 10% solution?

  1 7/9 ounces

Step-by-step explanation:

The final solution will be 9 parts water and 1 part hydrogen peroxide (so that hydrogen peroxide makes up 1 of 10 parts of the solution).

Then each "part" is (16 ounces)/9 = 1 7/9 ounces.

1 7/9 ounces of hydrogen peroxide must be added to 16 ounces of water to make a 10% solution.

Check

The total amount of solution is 16 +1 7/9 = 17 7/9 ounces = 160/9 ounces. The amount that is hydrogen peroxide is 16/9 ounces, so the fraction that is hydrogen peroxide is ...

  (16/9) / (160/9) = 16/160 = 1/10 = 10%

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.