A taxi travels 25 kilometers east of an airport .Then ,it travels from that point to a point that is 40 kilometers west of the airport. Finally , the taxi returns to the airport. How far did the taxi travel

130 km

Step-by-step explanation:

First he goes 25 km east of airport so D1 = 25 km

He them returns and goes 40 km west of airport i-e first he will come back to airport travelling 25 km back and then he will go west of airport 4o km - so total distance = D2 = 25+40= 65 km

He then returns back  again and travels 40 km back, so distance back from west =D3=40 km

So, total distance he traveled = D1=D2+D3 =25+65+40=130 km

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.