When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has a student-t statistic of –2.50?

P-value = 0.009997                                                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 24

Nature of test: One-tailed test(Left tailed test)

We have to calculate the p-value.

Degree of freedom = n - 1 = 23

We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.

P-value = 0.009997

0.009997 is the  probability of a value being to the left of a number that has a student-t statistic of –2.50.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

the answer is -1 for this question

step-by-step explanation: