How do I do this? It is a regular hexagon with a height of 30. We have to find the perimeter of it.

Perimeter = 60√3

Step-by-step explanation:

I can't see any other way of doing this than by using trig.

Draw IS which is also 30.

Now we use that midpoint. Cos(30) = 15/IL

Cos(30) = √3/2 = adjacent / hypotenuse

The adjacent side = 15

15/(√3/2) = hypotenuse

Hypotenuse = 15*2 √3 / 3 = 10 √3

The hypotenuse is IL which is one of the sides.

The perimeter = 6*IL = 6 * 10 √3 = 60√3

Your answer is very close to mine. I'd sure like to know how you did it.

answer: x=60