Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript negative 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1, then the quadratic equation in u is u^2-2u-15(-5)(u+3) (u-5 )(u+3 ).

  u^2-2u-15 = 0

Step-by-step explanation:

If you make the substitution ...

  u equals x Superscript negative 1 Baseline

then you can rewrite the equation as shown above.

y=mx+b is the final answer!   : )

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions