Evaluate f(x)=(2x+1)^2 at -2,-1,0,1 and 2

at -2=9

at -1= 1

at 0=1

at 1= 9

at 2=25

Step-by-step explanation:

F(x)= (2x + 1)²

at -2

F(x) = (2(-2) + 1)²

= (-4+1)²

=(-3)²

=9.

Same goes with all points

how am i supposed to answer

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180