One of Kepler's three laws of planetary motion states that the square of the period, P, of a body orbiting the sun is proportional to the cube of Its average distance, d, from the sun. The Earth has a period of 365 days and its distance from the sun is approximately 93,000,000 miles. (a) Find P as a function of d. P(d) = squareroot (1.6563*10^(-19)d) (b) The planet Uranus has an average distance from the sun of 1, 800,000,000 miles. How many earth days are In a Uranus year in other words, what is the period of the planet Uranus? days (Round to nearest day and do not enter commas in your answer.)

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

unless if u could do my questions, if not i wouldn't want to

13cm

step-by-step explanation:

(apex)