Mathematics, 13.02.2020 20:58 61497

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by line A1, 5% need rework to remedy a defect, whereas8% of A2's components need rework and 10% of A3's need rework. Suppose that 50% of all components are produced by Line A1, 30% areproduced by line A2, and 20% come from line A3. if a randomlyselected component needs rework, what is the probability that itcame from line A1?

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Answer from: jdkrisdaimcc11

If a randomly selected component needs rework, the probability that it came from line A1 is 36.23%.

Given that a company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component, and of those manufactured by line A1, 5% need rework to remedy a defect, whereas 8% of A2's components need rework and 10% of A3's need rework, supposing that 50% of all components are produced by Line A1, 30% are produced by line A2, and 20% come from line A3, if a randomly selected component needs rework, to determine what is the probability that it came from line A1 the following calculation must be performed:

0.5 x 0.05 = 0.025 0.025 + (0.3 x 0.08) + (0.2 x 0.1) = 0.025 + 0.024 + 0.02 = 0.069 69 = 100 25 = X 25 x 100/69 = X 36.23 = X

Therefore, if a randomly selected component needs rework, the probability that it came from line A1 is 36.23%.

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Answer from: phillswift2020

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote R as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Answer from: Quest

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Which statement about the frequency table is true?

Answer from: Quest

answer: there are x+184 pages in olivia's book.

step-by-step explanation:

let the total number of pages in the book which olive has already read be x.

then if olive has 184 pages left to read, then the total number of pages are in olive's book= pages she has read+pages she has left to read

therefore, the total number of pages in olivia's book= $x+184$

hence, there are x+184 pages in olivia's book.

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