The activity completion time of each of the 5 critical activities of a project follows normal distribution. If the mean activity completion time of each activity is 2 weeks, and the standard deviation of the activity completion time of each of the critical activity is 10, then what is the probability that the project would take between 9 and 13 week?

P(x = 9) and P(x = 13) is:

0.6551965

Step-by-step explanation:

By Z score,

,

P(x = 9 ) =

P(x =13) =

And these give:

P(x = 9) ==>  P(Z = 0.7) = 0.7580363

P(x = 13) ==>  P(Z = 1.1) = 0.8643339

Therefore, the probability that the project would take between 9 and 13 week = P(x = 9) * P(x =13) =  0.6551965.

For replication, see the R codes below:

Z1 = (9 - 2)/(10/sqrt(length(5)))

a = pnorm(Z1)

Z2 = (13 - 2)/(10/sqrt(length(5)))

b = pnorm(Z2)

a*b

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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