Find the position vector R(t) and velocity vector V(t), given the acceleration A(t) and initial position and velocity vectors R(0) and V(0), respectively.
A(t)= t^2i-2t^(1/2)j+e^(3t)k; R(0)= 2i+j-k; V(0)=i-j-2k

The fundamental theorem of calculus tells us that

So we have

and

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step-by-step explanation:

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341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.