Which function in vertex form is equivalent to f(x) = x2 6x 3? f(x) = (x 3)2 3 f(x) = (x 3)2 − 6 f(x) = (x 6)2 3 f(x) = (x 6)2 − 6

Some operators are missed.

Any way I can guess that the function is x^2+6x+3

To find the vertex form of the equation you need to form a perfect square.

To do that add and subtract 9:

x^2 + 6x + 9 +3 - 9 = (x^2+6x+9) + (3-9) = (x+3)^2 -6

f(x) = (x+3)^2 - 6

None because i don’t know.