A rectangular block of aluminum30 mm×60 mm×90 mm is placed in apressurechamber and subjected to a pressure of 100 MPa. If the modulus of elasticity is 75GPa andPoisson's ratio is 0.35, what will be the decrease in the longest side of the block, assuming thatthe material remains within the linear elastic region? What will be the decrease in the volume oftheblock? g

Step-by-step explanation:

we know that change is length is calculated by following strain relation

where strain is given as

plugging strain value in change in length formula

calculate the length on the longer side

              = 90 - 0.04008 = 89.95 mm

intial volume

change in volume

2/3

step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)