$\color[rgb]{0.35,0.35,0.35}\sqrt{5 0} \cdot\! \sqrt{6} \cdot \!\sqrt{27}$

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

Multiple choice or not?