5. A rectangular swimming pool is 25 feet wide
and the diagonal measure is 47 ft. How long is the
swimming pool to the nearest tenth of a foot?
(Leave answer as a decimal. Round to the nearest tenth)
Help please

Step-by-step explanation:

The width is 25ft

The diagonal is 47ft

The length can be calculated using pythagoras theorem

sqr Hypothenus= sqr opposite + sqr adjacent

47^2 = 25^2+ length^2

2209 = 625+ length^2

2209-625 = length^2

1584 = l^2

l = sqrt 1584 = 39.7994974843

Length = 39.8 ( nearest tenth)

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: