Of all the permutations of the letters in the word DOG, if you choose one at random, what is the probability that it is an actual English word?

1/3

Step-by-step explanation:

Total letters in DOG = 3

All possible permutations = 3! = 6

Words are DOG, GOD, OGD, ODG, DGO, GDO

Actual English words = 2 out of 6

Probability that it is an actual English word = 2/6 = 1/3

17.08

correct me if i am wrong.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.