A projector display a rectangular image on a wall. The height of the wall is x feet. The area (in square feet) of the projection by x^2-12x+32. The width of the projection is (x-4) feet. B Find the perimeter of the projection when the height of wall is 10 feet

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

i would say b) is your answer

sorry if im wrong

step-by-step explanation:

2 1/2 feet

step-by-step explanation: