Consider the following data: 14 21 23 19 16 15 20 20 21 25 24 18 17 23 26 18 16 15 24 21 16 19 21 23 20 23 14 13 14 14 12 26 19 25 15 23 25 25 19.
A. Develop a frequency distribution using classes of 12-14, 15-17, 18-20, 21-23, and 24-26.
B. Develop a frequency distribution and percent frequency distribution.

A.

Class interval frequency

12-14                  6      

15-17                  7

18-20                9

21-23                9

24-26                8

Total                39

B.

Class interval frequency  Percent frequency

12-14                  6                    0.15

15-17                  7                     0.18

18-20                9                     0.23

21-23                9                     0.23

24-26                8                     0.21

Total                39                   1

Step-by-step explanation:

a)

There are total 39 observation in the data. Note that sum of frequencies should be equal to the number of data values i.e. sum f=n=39.

Arranging the data values in the frequency distribution. The frequency depicts that number of times data value occurs in the data

Class interval frequency

12-14                  6      

15-17                  7

18-20                9

21-23                9

24-26                8

Total                39

The class interval were given and frequency for each class interval depicts the number of data values falls in this interval.

b)

The class interval are given and we already found the frequencies. Now we have to find percent frequencies for each class which can be calculated by dividing the frequency of respective class to the sum of frequencies. Also, sum of percent frequencies should be equal to 1.

Class interval frequency  Percent frequency

12-14                  6                    6/39=0.15

15-17                  7                     7/39=0.18

18-20                9                     9/39=0.23

21-23                9                     9/39=0.23

24-26                8                    8/39= 0.21

Total                39                   1

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

what's the question?

step-by-step explanation:

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