A triangle with 2 40 degree angles that surround a 5 inch side

The drawing in the attached figure

see the explanation

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal interior angles

In this problem

we have an isosceles triangle (because has two equal interior angles)

see the attached figure to better understand the problem

step 1

Find the length side AB

In the right triangle ABD

----> by CAH (adjacent side divided by the hypotenuse)

we have

---> because is an isosceles triangle (the height bisect the base)

substitute

Find the length side AC

we know that

AC=AB ----> by definition of isosceles triangle

so

step 2

Find the perimeter

step 3

Find the height AD

In the right triangle ABD

----> by TOA (opposite side divided by the adjacent side)

substitute the given values

Find the area of triangle

substitute

answer: b.36 feet

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation