Amos, Butch and Cody decide to settle their differences with a gunfight. The three cow-boys draw lots for the shooting order and then take one shot each until only one is left standing. Amos and Butch are sure shots and never miss. Cody, unfortunately, only hits his mark fifty percent of the time. From this information, who has the best chance of survival?

Amos/Butch

Step-by-step explanation:

Since Amos and Butch are sure shots, Cody hits only 50% of the time, and each of them have to fire shots, then the order of shots can be that:

Cody shot Amos and missed, Butch shot Cody and hit his target and Amos shot butch and also hit his target with Amos left standing

Or

It could also have been possible that Cody shot Butch and missed his target, Amos shot Cody and hit his target, Butch shot Amos and hit his target with Butch left standing

Hence Amos/Butch have the highest chance of survival.

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9