At a large university it is known that 51% of the students live on campus. The director of student life is going to take a random sample of 100 students. What is the probability that more than half of the sampled students live on campus?

Since an approximate method hasn't been specified,  we can use binomial distribution with n = 100, p = 0.51, q = 1 - p = 0.49

more than half means ≥ 51

P[x ≥ 50] = sum C(100,x) * 0.4^x *0.6^(200-x) for x = 51 to 100 = 0.54006

Step-by-step explanation:

Further explanation can be seen from:

https://www.wolframalpha.com/input/?i=sum+C%28100%2Cx%29+*+0.51%5Ex+*0.49%5E%28100-x%29+for+x+%3D+51+to+100

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

srry idk

step-by-step explanation: