Suppose you roll two fair dice. Create (or reference) a sample space to represent the situation then determine
each of these probabilities.

a. Getting an even sum OR a sum of 3

b. Getting doubles AND an even sum of at least 8.

Rolling two dice can output any number between 2 and 12. Here are the probabilities (given by how many combinations would yield that sum):

You get 2 if you roll (1, 1)

You get 3 if you roll (1, 2), (2, 1)

You get 4 if you roll (1, 3), (2, 2), (3, 1)

You get 5 if you roll (1, 4), (2, 3), (3, 2), (4, 1)

You get 6 if you roll (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

You get 7 if you roll (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

You get 8 if you roll (2, 6), (3, 5), (4, 4), (5, 3), (6, 2)

You get 9 if you roll (3, 6), (4, 5), (5, 4), (6, 3)

You get 10 if you roll (4, 6), (5, 5), (6, 4)

You get 11 if you roll (5, 6), (6, 5)

You get 12 if you roll (6, 6)

So, you get an even sum OR a 3 if you roll a total of 2, 3, 4, 6, 8, 10 or 12. The sum of their probabilities is

You get doubles and at least 8 if you get (4,4), (5,5) or (6,6). Each of these pairs happen with probability 1/36, for a total of

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x