The second angle of a triangle is 50° less than the first angle the third angle is 40° less than the first angle find the measurements of all three angles

First angle =

Secomd angle  =

Thirsd angle   =  

Step-by-step explanation:

Let  the first angle be x------------(1)

Then the second angle is 50° less than the first angle

Then the second angle will be x -50------------(2)

The third angle is 40° less than the first angle

Then the angle will be x - 40------------(3)

We know that, according to angle sum property , the sum of all the three angle will be 180 degrees

So adding all the 3 angles,

Now the second angle is

=>

=>

=>

The Third angle is

=>

=>

=>

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

step-by-step explanation: s