I have a bag with 3 fair dice. One is 4-sided, one is 6-sided, and one is 12-sided. I reach into the bag, pick one at random and roll it. The outcome of the roll is 4. What is the probability that I pulled out the 6-sided die?

0.407

Step-by-step explanation:

Let A be the event that you pull out the 6-sided dice, and B be the event that the out come of the roll is 4.

There are 3 dices with equal chance of getting pull out so P(A) = 1/3.

There are 3 ways to roll a 4 out of 4 + 6 + 12 = 22 options of 3 die. So P(B) = 3/22.

A|B is the event that you pull out the 6-sided dice, knowing that the out come of the roll is 4.

B|A is the event that the outcome of the roll is 4, knowing that you pull out the 6-sides dice, so P(B|A) = 1/6

Using bayes conditional theorem, we have

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

da freeck kinda math is this just drop out

step-by-step explanation: