A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, arandom sample of 200 cartridges is selected, and each cartridge is inspected. If the sample proportion of defectivecartridges is more than .02, the entire shipment is returned to the vendor. a. What is the approximate probability that a shipment will be returned if the true proportion of defective cartridges in theshipment is .05?b. What is the approximate probability that a shipment will not be returned ifthe true proportion of defective cartridges inthe shipment is .10?

(1) The probability that the shipment will be returned  if the true proportion of defective cartridges in the shipment is 0.05 is 0.9744.

(2) The probability that the shipment will not be returned if the true proportion of defective cartridges in the shipment is 0.10 is 0.00008.

Step-by-step explanation:

Let X = Number of defective cartridges.

The sample size is: n = 200.

The probability that the shipment is rejected is, p = 0.02.

The random variable X follows a Binomial distribution with parameters n and p.

But the sample size is too large, i.e. n = 200 > 30.

Then according to the normal approximation to binomial, if np ≥ 10 or n(1 - p) ≥ 10, the sampling distribution of sample proportion follows a normal distribution with mean

Check:

Thus, the sampling distribution of sample proportion follows a Normal distribution.

(1)

the mean and standard deviation:

The probability that the shipment will be returned  if the true proportion of defective cartridges in the shipment is 0.05 is:

Use the standard normal table for the probability.

Thus, the probability that the shipment will be returned  if the true proportion of defective cartridges in the shipment is 0.05 is 0.9744.

(2)

Compute the mean and standard deviation:

The probability that the shipment will not be returned if the true proportion of defective cartridges in the shipment is 0.10 is:

Use the standard normal table for the probability.

Thus, the probability that the shipment will not be returned if the true proportion of defective cartridges in the shipment is 0.10 is 0.00008.

50- 250 is correct i did that one too

step-by-step explanation:

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316