A person standing close to the edge on top of a 16-foot building throws a baseball vertically upward. The quadratic function s (t )equals negative 16 t squared plus 64 t plus 16 models the ball's height above the ground, s(t), in feet, t seconds after it was thrown. After how many seconds does the ball reach its maximum height? Round to the nearest tenth of a second if necessary. A. 1.5 seconds

maximum height = 80 feet

It reaches maximum height in 2 seconds

Step-by-step explanation:

A person standing close to the edge on top of a 16-foot building throws a baseball vertically upward.

To find maximum height we need to find the vertex

To find x coordinate of vertex use formula

a= -16 , b= 64

now we plug in 2 for x in s(t) to find maximum height at x=2

so maximum height = 80 feet

It reaches maximum height in 2 seconds

x=6 and x=3

beep beep imma sheep

your answer is -9

step-by-step explanation: