Jimmy walked from his house, to school, then to the store, and finally back home. The distance from the school to the store is 100 meters (100m) more than the distance from Jimmy's house to the school. The distance from the store to Jimmy's house is 175m more than the distance from his house to the school. If the total distance he walked was 1,475m, what is the distance from his house to the school in meters?

The distance from Jimmy's house to the school is 400 meters.

Step-by-step explanation:

Step 1; Assume that the distance between Jimmy's house and his school is x meters. So from the given data, we can form these

Distance from his house to the school = x,

Distance from his school to the store = Distance from his house to the school + 100 = x + 100,

Distance from the store to his house = Distance from his house to the school + 175 = x +175.

Step 2; It is given that the total distance Jimmy walked was 1,475 meters. Jimmy walked a total of three trips so,

x + x + 100 + x + 175 = 1,475,

3x + 275 = 1,475,

3x = 1,475 - 275 = 1,200,

x = 400.

So distance from Jimmy's house to school = 400 meters,

Distance from his school to the store = 400 + 100 = 500 meters,

Distance from the store to his house = 400 + 175 = 575 meters.

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.