A person who is 6 feet tall walks away from a flagpole toward the tip of the shadow of the flagpole. When the person is 12 feet from the flagpole, the tips of the person's shadow and the shadow cast by the flagpole coincide at a point 3 feet in front of the person.

h = 29.4 f

Step-by-step explanation: (see annex)

I conclude the question of the problem is the height " h " of the flagpole

From the draft in annex, is clear the angle ABC is common to the triangles

ABC and BDE

In triangle BDE  

BE = √ (3)² + (6)²         ⇒ BE = √9 + 36       ⇒BE = √45

BE = 6,71 f

then      sin ∠ ABC  =  6/6.71     ⇒   sin ∠ ABC  = 0,89

then arcsin 0,89      ∠ABC  =  63°

Now in triangle ABC

tan  ∠ ABC  = h/( 12 + 3 )        ⇒   tan  ∠ ABC  = h/15

tan ∠ 63°   =  1.96

Then       1.96  =  h/15

h  =  1.96 * 15

h = 29.4 f

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

the answer is b.6

step-by-step explanation: