Acountry's population in 1993 was 94 million. in 1999 in was 99 million. estimate the population in 2005 using the exponential growth formula. round your answer to the nearest millionth. p=ae^kt

Using the exponential growth formula P = Ae^kt, we can solve for the missing values.

Initially, let us solve for the growth factor k, using the values from 1993 and 1999.

In year 1999:
P = 99 million
A = 94 million
t = 1999 - 1993 = 6

Substituting the values into the equation:

99,000,000 = 94,000,000(e^k(6))
k = 8.6375x10^-3

Obtaining the population in 2005 using values from 1999:
P = ?
A = 99,000,000
k = 8.6375x10^-3
t = 2005 - 1999 = 6

Substituting the values into the equation:

P = 99,000,000(e^(8.6375x10^-3)(6))
P = 104,265,957.4

Approximating to the nearest million, the population in 2005 is 104 million.

Dis a correct answer