[] + [] + [] =30... Use this number below to complete find the solution...
1,3,5,7,9 and 15.

answer:

(5+1)+9+15

Just using the numbers given there, it's not possible, because odd + odd = even, even + odd = odd. 30 is an even number, the answer of 3 odd numbers must be odd, it's a contradiction.

If what people say is true, then the question is wrongly phrased its any number of operations within those three brackets must lead to 30. Then it becomes a lot easier. Such as 15 + 7 + (7 + 1). That would give 30. But it assumes something that the question does not state explicitly and cannot be done that way. I still stick to my first point, it can't be done within the realm of math and just using three numbers, if not, then the latter is a way to solve it.

EDIT:   This question has come up many times, Any odd number can be expressed as the following,

Let n,m,p be an odd number,

n=1(mod 2),m=1(mod 2),p=1(mod 2)

n+m+p=1+1+1(mod 2)

Let's call n+m+p as x

=>x=3(mod 2)

Numbers in modulo n can be added, I'll write a small proof for it below,

a=b(mod n),c=d(mod n)

a+c=b+d(mod n)

We can rewrite b and d in the following way,

n|(b−a)=>b−a=n∗p (for some integer p) b=a+np

b=a+np,d=c+nq

b+d=a+np+c+nq

b+d=a+c+n(p+q)

Now we have shown that our result is true, moving forward,

3=1(mod 2)

x=1(mod 2)

Therefore the sum of three odd numbers can never be even. It will always be congruent to 1 in mod 2.

Step-by-step explanation:

plz brainliest

mx+89b(-98)nb

step-by-step explanation:

5+2x=a

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