Could somebody please help me with this?

(x-3)^2=42

Step-by-step explanation:

If you breaks the equation down

(X-3).(X-3)=42

x^2-3x-3x+9=42

x^2-6x+9=42

Collect like term

x^2-6x=42-9

x^2-6x=33

Therefore

x^2-6x-33=0

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

i believe that the answer is

b. y-1=-2(x-4)

hope this !