Consider the equation:
10x - 4= ax + b

Find a value for a and a value for b so the equation has no solution.

also i rlly need someone to talk to ive been doing work all day :)

(b can be anything you want as long as its not -4)

Work Shown:

Note how ax+b looks really similar to mx+b. All that is different is the slope m is replaced with the letter 'a'.

On the left side, 10x-4 is in the form mx+b with m = 10 as the slope. If we made a = 10, then the slope of the right side would also be 10 and we'd have parallel lines as long as b is not -4.

If b = -4 along with a = 10, then we'd have 10x-4 on the right hand side. This leads to infinitely many solutions.

If b is anything but -4, and a = 10, then we have two parallel lines with no solutions since parallel lines never cross. I'm picking b = 0 since 0 is the easiest number to pick on. You can pick anything you want (as long as its not -4 of course) for the value of b.

90% rotation

step-by-step explanation:

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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