One of the roots of the quadratic equation x^2−5mx+6m^2=0 is 36. Find the greatest possible value of the second root. 100PTS!!!

The greatest possible value is 54

Step-by-step explanation:

Solve the quadratic equation

Given

x² - 5mx + 6m² = 0

We can rewrite this as

x² - 3mx - 2mx + 6m² = 0

(x² - 3mx) - (2mx - 6m²) = 0

x(x - 3m) - 2m(x - 3m) = 0

(x - 2m)(x - 3m) = 0

x - 2m = 0 or x - 3m = 0

So,

x = 2m or x = 3m .

2m and 3m are the roots of the equation.

Since one of the roots is 36

Assume

2m = 36

m = 36/2 = 18

3m is

3(18) = 54

If 3m = 36

m = 12

And

2m = 2(12) = 24.

The greatest possible value is 54

answer: 800

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry