Newton’s law of cooling states that for a cooling substance with initial temperature t0 , the temperature t(t) after t minutes can be modeled by the equation t(t)=ts+(t0−ts)e−kt , where ts is the surrounding temperature and k is the substance’s cooling rate. a liquid substance is heated to 80°c . upon being removed from the heat, it cools to 60°c in 12 min. what is the substance’s cooling rate when the surrounding air temperature is 50°c ? the substances cooling rate when the surrounding air temperature is 50c is 0.0916.0.06870.07320.08130.0916