Karen set her watch 1 second behind, and it falls behind another 2 seconds every day. how many days has it been since karen last set her watch if the watch is 9 seconds behind? write and solve an equation to find the answer.

The equation to find the answer is  .

It has been 5 days since Karen has set her watch.

Step-by-step explanation:

Given:

Karen set her watch 1 second behind

So we will consider;

First term 'a'  = 1 second

Also Given :

it falls behind another 2 seconds every day.

So we can consider;

Common difference = 2

We need to find number of days it has been 9 seconds since Karen last set her watch

Solution:

Let number of days be represented by 'n'.

Also Let

Now By Applying formula for Arithmetic Progression we get;

Substituting the given values we get;

Hence The equation to find the answer is  .

On Solving the above equation we get;

Subtracting both side by 1 we get;

Now Dividing both side by 2 we get;

Adding 1 on both side we get;

Hence It has been 5 days since Karen has set her watch.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2