Two systems of equations are shown below. the first equation in system b is the original equation in system a. the second equation in system b is the sum of that equation and a multiple of the second equation in system a. a. 1/2 x 3y = 11 → 1/2 x 3y = 11 5x − y = 17 → 15x − 3y = 51 15 1/2 x = 62 b. 1/2 x 3y = 11 15 1/2 x = 62

x = 4, y=3

Step-by-step explanation:

System A :

Since we are given that System b first equation is same as first equation of system a

⇒ System b :

first equation :

We are also given that second equation in system b is the sum of that equation and a multiple of the second equation in system a.

⇒

⇒

Now add this equation with first equation of system a.

Thus second equation of system b is

⇒

⇒

⇒

⇒

Now to find y put value of x in any equation

we will put in first equation of system a i.e.

⇒

⇒

⇒

⇒

⇒

⇒

Thus SYSTEM A :

        SYSTEM B :

Solution of system of equations : x = 4, y=3

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step-by-step explanation:

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-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x