Asap for brainliest:
the mean score for a standardized is 1700 points. the results are normally distributed with a standard deviation of 75 points. if 10,000 students take the exam, how many would you expect to score above 1850 points? show work

228 students

Step-by-step explanation:

Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = test reults

µ = mean score

σ = standard deviation

From the information given,

µ = 1700 points

σ = 75 points

We want to find the probability of students expected to score above 1850 points. It is expressed as

P(x > 1850) = 1 - P(x ≤ 1850)

For x = 1850,

z = (1850 - 1700)/75 = 150/75 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.97725

P(x > 1850) = 1 - 0.97725 = 0.02275

If 10,000 students take the exam, then the number of students you would expect to score above 1850 points is

0.02275 × 10000 = 228 students

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

answer: sine

step-by-step explanation: