Two trains left metropolis at the same time. one traveled south at 50 mph. we are traveling east at 40 mph. how far apart were the trades at the end of three hours

they would be 192 miles apart after 3 hours

Step-by-step explanation:

The two trains left Metropolis at the same time.

One traveled south at 50 mph.

Distance travelled = speed × time

After 3 hours, the distance travelled by the first train southwards would be

3 × 50 = 150 miles

The other train travelled eastwards at 40 mph. After 3 hours, the distance travelled by the second train eastwards would be

3 × 40 = 120 miles

The distance between the trains at the end of 3 hours would be the hypotenuse of the triangle formed by the southward and eastward movement of both trains.

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side². Therefore,

Hypotenuse² = 150² + 120² = 36900

Hypotenuse = √36900 = 192 miles

overpriced

step-by-step explanation:

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: